Integrand size = 16, antiderivative size = 89 \[ \int \frac {x^{5/2}}{(2-b x)^{5/2}} \, dx=\frac {2 x^{5/2}}{3 b (2-b x)^{3/2}}-\frac {10 x^{3/2}}{3 b^2 \sqrt {2-b x}}-\frac {5 \sqrt {x} \sqrt {2-b x}}{b^3}+\frac {10 \arcsin \left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {2}}\right )}{b^{7/2}} \]
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Time = 0.01 (sec) , antiderivative size = 89, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {49, 52, 56, 222} \[ \int \frac {x^{5/2}}{(2-b x)^{5/2}} \, dx=\frac {10 \arcsin \left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {2}}\right )}{b^{7/2}}-\frac {5 \sqrt {x} \sqrt {2-b x}}{b^3}-\frac {10 x^{3/2}}{3 b^2 \sqrt {2-b x}}+\frac {2 x^{5/2}}{3 b (2-b x)^{3/2}} \]
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Rule 49
Rule 52
Rule 56
Rule 222
Rubi steps \begin{align*} \text {integral}& = \frac {2 x^{5/2}}{3 b (2-b x)^{3/2}}-\frac {5 \int \frac {x^{3/2}}{(2-b x)^{3/2}} \, dx}{3 b} \\ & = \frac {2 x^{5/2}}{3 b (2-b x)^{3/2}}-\frac {10 x^{3/2}}{3 b^2 \sqrt {2-b x}}+\frac {5 \int \frac {\sqrt {x}}{\sqrt {2-b x}} \, dx}{b^2} \\ & = \frac {2 x^{5/2}}{3 b (2-b x)^{3/2}}-\frac {10 x^{3/2}}{3 b^2 \sqrt {2-b x}}-\frac {5 \sqrt {x} \sqrt {2-b x}}{b^3}+\frac {5 \int \frac {1}{\sqrt {x} \sqrt {2-b x}} \, dx}{b^3} \\ & = \frac {2 x^{5/2}}{3 b (2-b x)^{3/2}}-\frac {10 x^{3/2}}{3 b^2 \sqrt {2-b x}}-\frac {5 \sqrt {x} \sqrt {2-b x}}{b^3}+\frac {10 \text {Subst}\left (\int \frac {1}{\sqrt {2-b x^2}} \, dx,x,\sqrt {x}\right )}{b^3} \\ & = \frac {2 x^{5/2}}{3 b (2-b x)^{3/2}}-\frac {10 x^{3/2}}{3 b^2 \sqrt {2-b x}}-\frac {5 \sqrt {x} \sqrt {2-b x}}{b^3}+\frac {10 \sin ^{-1}\left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {2}}\right )}{b^{7/2}} \\ \end{align*}
Time = 0.24 (sec) , antiderivative size = 76, normalized size of antiderivative = 0.85 \[ \int \frac {x^{5/2}}{(2-b x)^{5/2}} \, dx=-\frac {\sqrt {x} \left (60-40 b x+3 b^2 x^2\right )}{3 b^3 (2-b x)^{3/2}}-\frac {20 \arctan \left (\frac {\sqrt {b} \sqrt {x}}{\sqrt {2}-\sqrt {2-b x}}\right )}{b^{7/2}} \]
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Time = 0.12 (sec) , antiderivative size = 81, normalized size of antiderivative = 0.91
method | result | size |
meijerg | \(-\frac {8 \left (-\frac {\sqrt {\pi }\, \sqrt {x}\, \sqrt {2}\, \left (-b \right )^{\frac {7}{2}} \left (\frac {21}{4} b^{2} x^{2}-70 b x +105\right )}{56 b^{3} \left (-\frac {b x}{2}+1\right )^{\frac {3}{2}}}+\frac {15 \sqrt {\pi }\, \left (-b \right )^{\frac {7}{2}} \arcsin \left (\frac {\sqrt {b}\, \sqrt {x}\, \sqrt {2}}{2}\right )}{4 b^{\frac {7}{2}}}\right )}{3 \left (-b \right )^{\frac {5}{2}} \sqrt {\pi }\, b}\) | \(81\) |
risch | \(\frac {\sqrt {x}\, \left (b x -2\right ) \sqrt {\left (-b x +2\right ) x}}{b^{3} \sqrt {-x \left (b x -2\right )}\, \sqrt {-b x +2}}+\frac {\left (\frac {5 \arctan \left (\frac {\sqrt {b}\, \left (x -\frac {1}{b}\right )}{\sqrt {-b \,x^{2}+2 x}}\right )}{b^{\frac {7}{2}}}+\frac {8 \sqrt {-b \left (x -\frac {2}{b}\right )^{2}-2 x +\frac {4}{b}}}{3 b^{5} \left (x -\frac {2}{b}\right )^{2}}+\frac {28 \sqrt {-b \left (x -\frac {2}{b}\right )^{2}-2 x +\frac {4}{b}}}{3 b^{4} \left (x -\frac {2}{b}\right )}\right ) \sqrt {\left (-b x +2\right ) x}}{\sqrt {x}\, \sqrt {-b x +2}}\) | \(168\) |
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Time = 0.25 (sec) , antiderivative size = 187, normalized size of antiderivative = 2.10 \[ \int \frac {x^{5/2}}{(2-b x)^{5/2}} \, dx=\left [-\frac {15 \, {\left (b^{2} x^{2} - 4 \, b x + 4\right )} \sqrt {-b} \log \left (-b x + \sqrt {-b x + 2} \sqrt {-b} \sqrt {x} + 1\right ) + {\left (3 \, b^{3} x^{2} - 40 \, b^{2} x + 60 \, b\right )} \sqrt {-b x + 2} \sqrt {x}}{3 \, {\left (b^{6} x^{2} - 4 \, b^{5} x + 4 \, b^{4}\right )}}, -\frac {30 \, {\left (b^{2} x^{2} - 4 \, b x + 4\right )} \sqrt {b} \arctan \left (\frac {\sqrt {-b x + 2}}{\sqrt {b} \sqrt {x}}\right ) + {\left (3 \, b^{3} x^{2} - 40 \, b^{2} x + 60 \, b\right )} \sqrt {-b x + 2} \sqrt {x}}{3 \, {\left (b^{6} x^{2} - 4 \, b^{5} x + 4 \, b^{4}\right )}}\right ] \]
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Result contains complex when optimal does not.
Time = 6.00 (sec) , antiderivative size = 751, normalized size of antiderivative = 8.44 \[ \int \frac {x^{5/2}}{(2-b x)^{5/2}} \, dx=\begin {cases} - \frac {3 i b^{\frac {23}{2}} x^{15}}{3 b^{\frac {27}{2}} x^{\frac {27}{2}} \sqrt {b x - 2} - 6 b^{\frac {25}{2}} x^{\frac {25}{2}} \sqrt {b x - 2}} + \frac {40 i b^{\frac {21}{2}} x^{14}}{3 b^{\frac {27}{2}} x^{\frac {27}{2}} \sqrt {b x - 2} - 6 b^{\frac {25}{2}} x^{\frac {25}{2}} \sqrt {b x - 2}} - \frac {60 i b^{\frac {19}{2}} x^{13}}{3 b^{\frac {27}{2}} x^{\frac {27}{2}} \sqrt {b x - 2} - 6 b^{\frac {25}{2}} x^{\frac {25}{2}} \sqrt {b x - 2}} - \frac {30 i b^{10} x^{\frac {27}{2}} \sqrt {b x - 2} \operatorname {acosh}{\left (\frac {\sqrt {2} \sqrt {b} \sqrt {x}}{2} \right )}}{3 b^{\frac {27}{2}} x^{\frac {27}{2}} \sqrt {b x - 2} - 6 b^{\frac {25}{2}} x^{\frac {25}{2}} \sqrt {b x - 2}} + \frac {15 \pi b^{10} x^{\frac {27}{2}} \sqrt {b x - 2}}{3 b^{\frac {27}{2}} x^{\frac {27}{2}} \sqrt {b x - 2} - 6 b^{\frac {25}{2}} x^{\frac {25}{2}} \sqrt {b x - 2}} + \frac {60 i b^{9} x^{\frac {25}{2}} \sqrt {b x - 2} \operatorname {acosh}{\left (\frac {\sqrt {2} \sqrt {b} \sqrt {x}}{2} \right )}}{3 b^{\frac {27}{2}} x^{\frac {27}{2}} \sqrt {b x - 2} - 6 b^{\frac {25}{2}} x^{\frac {25}{2}} \sqrt {b x - 2}} - \frac {30 \pi b^{9} x^{\frac {25}{2}} \sqrt {b x - 2}}{3 b^{\frac {27}{2}} x^{\frac {27}{2}} \sqrt {b x - 2} - 6 b^{\frac {25}{2}} x^{\frac {25}{2}} \sqrt {b x - 2}} & \text {for}\: \left |{b x}\right | > 2 \\\frac {3 b^{\frac {23}{2}} x^{15}}{3 b^{\frac {27}{2}} x^{\frac {27}{2}} \sqrt {- b x + 2} - 6 b^{\frac {25}{2}} x^{\frac {25}{2}} \sqrt {- b x + 2}} - \frac {40 b^{\frac {21}{2}} x^{14}}{3 b^{\frac {27}{2}} x^{\frac {27}{2}} \sqrt {- b x + 2} - 6 b^{\frac {25}{2}} x^{\frac {25}{2}} \sqrt {- b x + 2}} + \frac {60 b^{\frac {19}{2}} x^{13}}{3 b^{\frac {27}{2}} x^{\frac {27}{2}} \sqrt {- b x + 2} - 6 b^{\frac {25}{2}} x^{\frac {25}{2}} \sqrt {- b x + 2}} + \frac {30 b^{10} x^{\frac {27}{2}} \sqrt {- b x + 2} \operatorname {asin}{\left (\frac {\sqrt {2} \sqrt {b} \sqrt {x}}{2} \right )}}{3 b^{\frac {27}{2}} x^{\frac {27}{2}} \sqrt {- b x + 2} - 6 b^{\frac {25}{2}} x^{\frac {25}{2}} \sqrt {- b x + 2}} - \frac {60 b^{9} x^{\frac {25}{2}} \sqrt {- b x + 2} \operatorname {asin}{\left (\frac {\sqrt {2} \sqrt {b} \sqrt {x}}{2} \right )}}{3 b^{\frac {27}{2}} x^{\frac {27}{2}} \sqrt {- b x + 2} - 6 b^{\frac {25}{2}} x^{\frac {25}{2}} \sqrt {- b x + 2}} & \text {otherwise} \end {cases} \]
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Time = 0.30 (sec) , antiderivative size = 86, normalized size of antiderivative = 0.97 \[ \int \frac {x^{5/2}}{(2-b x)^{5/2}} \, dx=\frac {2 \, {\left (2 \, b^{2} + \frac {10 \, {\left (b x - 2\right )} b}{x} - \frac {15 \, {\left (b x - 2\right )}^{2}}{x^{2}}\right )}}{3 \, {\left (\frac {{\left (-b x + 2\right )}^{\frac {3}{2}} b^{4}}{x^{\frac {3}{2}}} + \frac {{\left (-b x + 2\right )}^{\frac {5}{2}} b^{3}}{x^{\frac {5}{2}}}\right )}} - \frac {10 \, \arctan \left (\frac {\sqrt {-b x + 2}}{\sqrt {b} \sqrt {x}}\right )}{b^{\frac {7}{2}}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 200 vs. \(2 (66) = 132\).
Time = 1.52 (sec) , antiderivative size = 200, normalized size of antiderivative = 2.25 \[ \int \frac {x^{5/2}}{(2-b x)^{5/2}} \, dx=\frac {{\left (\frac {15 \, \log \left ({\left (\sqrt {-b x + 2} \sqrt {-b} - \sqrt {{\left (b x - 2\right )} b + 2 \, b}\right )}^{2}\right )}{\sqrt {-b} b^{2}} - \frac {3 \, \sqrt {{\left (b x - 2\right )} b + 2 \, b} \sqrt {-b x + 2}}{b^{3}} - \frac {16 \, {\left (9 \, {\left (\sqrt {-b x + 2} \sqrt {-b} - \sqrt {{\left (b x - 2\right )} b + 2 \, b}\right )}^{4} - 24 \, {\left (\sqrt {-b x + 2} \sqrt {-b} - \sqrt {{\left (b x - 2\right )} b + 2 \, b}\right )}^{2} b + 28 \, b^{2}\right )}}{{\left ({\left (\sqrt {-b x + 2} \sqrt {-b} - \sqrt {{\left (b x - 2\right )} b + 2 \, b}\right )}^{2} - 2 \, b\right )}^{3} \sqrt {-b} b}\right )} {\left | b \right |}}{3 \, b^{2}} \]
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Timed out. \[ \int \frac {x^{5/2}}{(2-b x)^{5/2}} \, dx=\int \frac {x^{5/2}}{{\left (2-b\,x\right )}^{5/2}} \,d x \]
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